1Z0-830 PDF QUESTIONS [2025]-RIGHT PREPARATION MATERIAL

1z0-830 PDF Questions [2025]-Right Preparation Material

1z0-830 PDF Questions [2025]-Right Preparation Material

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Oracle Java SE 21 Developer Professional Sample Questions (Q47-Q52):

NEW QUESTION # 47
Given:
java
var now = LocalDate.now();
var format1 = new DateTimeFormatter(ISO_WEEK_DATE);
var format2 = DateTimeFormatter.ISO_WEEK_DATE;
var format3 = new DateFormat(WEEK_OF_YEAR_FIELD);
var format4 = DateFormat.getDateInstance(WEEK_OF_YEAR_FIELD);
System.out.println(now.format(REPLACE_HERE));
Which variable prints 2025-W01-2 (present-day is 12/31/2024)?

  • A. format2
  • B. format4
  • C. format3
  • D. format1

Answer: A

Explanation:
In this code, now is assigned the current date using LocalDate.now(). The goal is to format this date to the ISO week date format, which represents dates in the YYYY-'W'WW-E pattern, where:
* YYYY: Week-based year
* 'W': Literal 'W' character
* WW: Week number
* E: Day of the week
Given that the present day is December 31, 2024, this date falls in the first week of the week-based year 2025.
Therefore, the ISO week date representation would be 2025-W01-2, where '2' denotes Tuesday.
Among the provided formatters:
* format1: This line attempts to create a DateTimeFormatter using a constructor, which is incorrect because DateTimeFormatter does not have a public constructor that accepts a pattern directly. This would result in a compilation error.
* format2: This is correctly assigned the predefined DateTimeFormatter.ISO_WEEK_DATE, which formats dates in the ISO week date format.
* format3: This line attempts to create a DateFormat instance using a field, which is incorrect because DateFormat does not have such a constructor. This would result in a compilation error.
* format4: This line attempts to get a DateFormat instance using an integer field, which is incorrect because DateFormat.getDateInstance() does not accept such parameters. This would result in a compilation error.
Therefore, the only correct and applicable formatter is format2. Using format2 in the now.format() method will produce the desired output: 2025-W01-2.


NEW QUESTION # 48
Given:
java
List<Integer> integers = List.of(0, 1, 2);
integers.stream()
.peek(System.out::print)
.limit(2)
.forEach(i -> {});
What is the output of the given code fragment?

  • A. Compilation fails
  • B. Nothing
  • C. 012
  • D. An exception is thrown
  • E. 01

Answer: E

Explanation:
In this code, a list of integers integers is created containing the elements 0, 1, and 2. A stream is then created from this list, and the following operations are performed in sequence:
* peek(System.out::print):
* The peek method is an intermediate operation that allows performing an action on each element as it is encountered in the stream. In this case, System.out::print is used to print each element.
However, since peek is intermediate, the printing occurs only when a terminal operation is executed.
* limit(2):
* The limit method is another intermediate operation that truncates the stream to contain no more than the specified number of elements. Here, it limits the stream to the first 2 elements.
* forEach(i -> {}):
* The forEach method is a terminal operation that performs the given action on each element of the stream. In this case, the action is an empty lambda expression (i -> {}), which does nothing for each element.
The sequence of operations can be visualized as follows:
* Original Stream Elements: 0, 1, 2
* After peek(System.out::print): Elements are printed as they are encountered.
* After limit(2): Stream is truncated to 0, 1.
* After forEach(i -> {}): No additional action; serves to trigger the processing.
Therefore, the output of the code is 01, corresponding to the first two elements of the list being printed due to the peek operation.


NEW QUESTION # 49
Which of the following statements is correct about a final class?

  • A. It cannot extend another class.
  • B. The final keyword in its declaration must go right before the class keyword.
  • C. It cannot implement any interface.
  • D. It cannot be extended by any other class.
  • E. It must contain at least a final method.

Answer: D

Explanation:
In Java, the final keyword can be applied to classes, methods, and variables to impose certain restrictions.
Final Classes:
* Definition:A class declared with the final keyword is known as a final class.
* Purpose:Declaring a class as final prevents it from being subclassed. This is useful when you want to ensure that the class's implementation remains unchanged and cannot be extended or modified through inheritance.
Option Evaluations:
* A. The final keyword in its declaration must go right before the class keyword.
* This is correct. The syntax for declaring a final class is:
java
public final class ClassName {
// class body
}
* However, this statement is about syntax rather than the core characteristic of a final class.
* B. It must contain at least a final method.
* Incorrect. A final class can have zero or more methods, and none of them are required to be declared as final. The final keyword at the class level prevents inheritance, regardless of the methods' finality.
* C. It cannot be extended by any other class.
* Correct. The primary characteristic of a final class is that it cannot be subclassed. Attempting to do so will result in a compilation error.
* D. It cannot implement any interface.
* Incorrect. A final class can implement interfaces. Declaring a class as final restricts inheritance but does not prevent the class from implementing interfaces.
* E. It cannot extend another class.
* Incorrect. A final class can extend another class. The final keyword prevents the class from being subclassed but does not prevent it from being a subclass itself.
Therefore, the correct statement about a final class is option C: "It cannot be extended by any other class."


NEW QUESTION # 50
Given:
java
var _ = 3;
var $ = 7;
System.out.println(_ + $);
What is printed?

  • A. Compilation fails.
  • B. _$
  • C. 0
  • D. It throws an exception.

Answer: A

Explanation:
* The var keyword and identifier rules:
* The var keyword is used for local variable type inference introduced inJava 10.
* However,Java does not allow _ (underscore) as an identifiersinceJava 9.
* If we try to use _ as a variable name, the compiler will throw an error:
pgsql
error: as of release 9, '_' is a keyword, and may not be used as an identifier
* The $ symbol as an identifier:
* The $ characteris a valid identifierin Java.
* However, since _ is not allowed, the codefails to compile before even reaching $.
Thus,the correct answer is "Compilation fails."
References:
* Java SE 21 - var Local Variable Type Inference
* Java SE 9 - Restrictions on _ Identifier


NEW QUESTION # 51
Which two of the following aren't the correct ways to create a Stream?

  • A. Stream stream = new Stream();
  • B. Stream stream = Stream.ofNullable("a");
  • C. Stream stream = Stream.generate(() -> "a");
  • D. Stream<String> stream = Stream.builder().add("a").build();
  • E. Stream stream = Stream.of();
  • F. Stream stream = Stream.empty();

Answer: A,D


NEW QUESTION # 52
......

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